[Discuss] IPv6 question(s)

[BCLUG]

Craig Miller wrote on 2023-10-16 16:48:

> Typically a /64 is assigned to a VPS, which will give you more IP 
> addresses than you need.

I requested "a couple, or a /64, what ever is easiest for you guys", so 
I guess I got what I asked for.

Having 5 * /112 should give me quite a few? Or just 5?

When I run `ip addr show` I get:

     inet6 2607:5300:203:b716::1:2/112 scope global
        valid_lft forever preferred_lft forever
     inet6 2607:5300:203:b716::1:3/112 scope global
        valid_lft forever preferred_lft forever
     inet6 2607:5300:203:b716::1:4/112 scope global
        valid_lft forever preferred_lft forever
     inet6 2607:5300:203:b716::1:5/112 scope global
        valid_lft forever preferred_lft forever
     inet6 2607:5300:203:b716::1:6/112 scope global
        valid_lft forever preferred_lft forever

Is that somehow equivalent to a /64, being contiguous?

Sorry, my brain isn't up to trying to calculate this myself at the moment...


> To answer your question, since there are 128 bits in an IPv6 address, 
> 128-112=16 or 2^16 hosts in a /112 block.

That's... 65536 addresses * 5 = 327680 addresses. "!"


And, how would I extract, say, 1 single IPv6 from 
2607:5300:203:b716::1:6/112 -- what would that even look like?

I can ping the bare 2607:5300:203:b716::1:6 from another host, which 
leads me to think it's a single IP, but I'm unclear.



> I hope this helps,

Very informative, thanks!

rb